112 年 國立中山大學材料與光電科學學系前瞻應用材料碩士班《普通物理學》
第 1. 題40 分
Problem 1. [Mechanics: 40 points]
In the following, we consider particles only move in x-direction.
(a) [5 points] There are two springs, one with the elastic constant , and the other with elastic constant . If the two springs are in series, what is the effective elastic constant ?
(b) [5 points] Consider 2 identical atoms with mass , connected by a chemical bond modeled as a spring with elastic constant (a sigma bond). The center of mass is stationary (not moving). Solve the angular frequency of the vibration motion of the 2 atoms. (hint: it might be easier if using the result of (a))
(c) [5 points] There are two springs, one with the elastic constant , and the other with elastic constant . If the two springs are in parallel, what is the effective elastic constant ?
(d) [5 points] Consider 2 identical atoms with mass , connected by 2 chemical bonds (that is, a double bond) modeled as 2 springs with elastic constant . The center of mass is stationary (not moving). Solve the angular frequency of the vibration motion of the 2 atoms. (hint: use the result of (c))
(e) [10 points] Consider 2 non-identical atoms with mass and (such as a carbon and an oxygen atom), connected by a chemical bond modeled as a spring with elastic constant (a sigma bond). The center of mass is stationary (not moving). Solve the angular frequency of the vibration motion of the 2 atoms.
(f) [5 points] Consider 2 non-identical atoms with mass and (such as a carbon and an oxygen atom), connected by 3 chemical bonds modeled as 3 springs with the same elastic constant (a sigma bond). (i) solve the angular frequency of the vibration motion of the 2 atoms, and (ii) compare the obtained frequency with the single bond case above.
(g) [5 points] Carbon dioxide can be modeled as one carbon atom and two oxygen atoms linked by springs (double bonds). How many are the vibrational modes? Please give a proper argument, not just giving the answer.
登入後即可作答並保存紀錄。
核心觀念
本題核心是「等效彈簧常數」與「簡諧運動」:
- 串聯彈簧承受相同的力,總伸長量為各彈簧伸長量之和。
- 並聯彈簧的伸長量相同,總恢復力為各彈簧恢復力之和。
- 雙原子振動可用相對座標描述,其等效質量為約化質量
- 振動角頻率為
題目限定粒子只沿 方向運動,因此只需討論縱向振動。
解題方法
(a)兩彈簧串聯
串聯時兩彈簧承受相同的力 。設兩彈簧伸長量分別為 、,總伸長量為 :
由虎克定律:
因此:
總伸長量為:
定義等效彈簧常數 :
所以:
得到:
(b)兩個質量相同的原子,以一個化學鍵相連
兩原子質量皆為 ,化學鍵的彈簧常數為 。
質心固定,因此兩原子的位移大小相等、方向相反。令兩原子的位移為:
化學鍵的伸長量為兩端相對位移:
第一個原子受到的恢復力為:
由牛頓第二定律:
整理為簡諧運動方程:
因此角頻率為:
也可使用約化質量:
由 同樣得到:
(c)兩彈簧並聯
並聯時兩彈簧的伸長量相同,設共同伸長量為 。
各彈簧的恢復力為:
總恢復力:
因此等效彈簧常數為:
(d)兩個相同原子,以雙鍵相連
雙鍵由兩條相同的化學鍵構成,每條彈簧常數均為 。兩條彈簧並聯,因此:
兩原子的約化質量仍為:
故角頻率:
因此:
與單鍵結果比較:
所以雙鍵的振動角頻率是單鍵的 倍。
(e)兩個不同質量的原子,以單鍵相連
兩原子質量分別為 與 ,單鍵彈簧常數為 。
系統的約化質量為:
振動角頻率為:
代入約化質量:
因此:
也可由質心固定直接推導。設兩原子位移為 與 ,質心固定代表:
兩原子的相對位移為:
系統的相對運動方程為:
因此:
所得角頻率即為上式。
(f)兩個不同質量的原子,以三重鍵相連
第 2. 題35 分
Problem 2. [Electromagnetism: 35 points]
The electric field at a distance r from a point charge Q is:
where is the unit vector along the vector . The electric potential is:
Consider the following questions in the vacuum, and use the units in the above formula.
(a) [5 points] If there are two point charges and , separated by a distance , as shown in the figure below. The magnitude of the dipole moment of these two point charges is then . Write down the electric potential at (the origin is at the middle of the two charges), using those quantities given in the figure.
(b) [5 points] Prove .
(c) [5 points] Use the approximation if to show: when (measuring the potential far away from the dipole), .
(d) [10 points] When (measuring the potential far away from the dipole), show the electric potential .
(e) [10 points] From the above result, calculate the electric field far away from the dipole using:
登入後即可作答並保存紀錄。
核心觀念
本題考查電偶極子的:
- 電位疊加原理;
- 電偶極矩定義;
- 二項式近似
- 球座標中的梯度,以及由電位求電場:
令偶極子中心為原點,偶極軸取為 軸, 位於 , 位於 。偶極矩方向由 指向 ,因此
觀測點與偶極軸的夾角為 。
(a) 電位的精確表示式
由電位的疊加原理,兩個點電荷產生的總電位為
觀測點到 與 的距離分別為
以及
因此
即
這是任意位置的精確電位。
(b) 證明遠處電位為
當觀測距離遠大於偶極子長度時,,可將兩個距離近似為
因此
令
則
而
相減得
代入 :
由 ,得到
這就是電偶極子的遠場電位。
(c) 使用二項式近似
精確距離可寫成
當 時,保留一階小量:
利用
可得
以及
因此,兩個電荷各自的電位近似為
第 3. 題10 分
Problem 3. [Thermodynamics: 10 points]
(a) [5 points] A gas is enclosed in a cylinder with a moveable piston, and follows the equation: .
where is the pressure, and is the volume of the gas. Find the work done when the volume is
compressed from to , with a known initial pressure (the final pressure is not known).
(b) [5 points] The Maxwell-Boltzmann distribution of the speed v of the particle is:
where is the mass of the particle, is the Boltzmann constant, and is the temperature. Calculate
the most probable speed , which corresponds to the maximum value of .
登入後即可作答並保存紀錄。
本題主要考察熱力學中的功的計算以及統計物理中的速度分佈函數求極值。
3. (a) 氣體壓縮過程的功
此題描述了一個氣體遵循 的過程,並要求計算從 壓縮到 所做的功。
設 ,其中 是常數。
因此,。
功的定義為 。
將 的表達式代入:
計算積分:
所以:
我們需要將常數 用已知的初始條件 和 來表示。
由 ,我們有 。
代入 。
另外一種表達方式:
由於 ,所以 。
。
。
將 替換成 。
第 4. 題15 分
Problem 4. [Waves/Optics/Modern physics: 15 points]
If a propagating wave along the x direction has the form , where is the
position, is the time, is a constant amplitude and is a constant phase.
(a) [5 points] (i) Show that this wave function satisfies the wave equation
(ii) express the velocity using , , , or .
(b) [5 points] The wave is a periodic function of the time, so for arbitrary
(where is the period). Use this relation, express the period with , , , and .
(c) [5 points] The wave is a periodic function of the position, so for arbitrary
(where is the wave length). Use this relation, express the wave length with , , , and .
登入後即可作答並保存紀錄。
本題主要考察平面波的波動方程、週期和波長的計算。
4. (a) 波動函數的波動方程驗證與速度求解
給定的波函數為 。
(i) 驗證波動方程 。
首先計算對 的二階偏導數:
接下來計算對 的二階偏導數:
將這兩個結果代入波動方程:
由於波沿 方向傳播,速度 可以是正的或負的。通常我們取正值表示沿 正方向傳播,即 。
(ii) 表達速度 。
從上面的推導,我們得到 。
因此,速度 為:
注意,速度 的值與振幅 和相位 無關。